Python 基础教程

Python 练习实例89

题目：某个公司采用公用电话传递数据，数据是四位的整数，在传递过程中是加密的，加密规则如下：每位数字都加上5,然后用和除以10的余数代替该数字，再将第一位和第四位交换，第二位和第三位交换。

程序分析：无。

程序源代码：

实例

#!/usr/bin/python # -*- coding: UTF-8 -*- from sys import stdout if __name__ == '__main__': a = int(raw_input('输入四个数字:\n')) aa = [] aa.append(a % 10) aa.append(a % 100 / 10) aa.append(a % 1000 / 100) aa.append(a / 1000) for i in range(4): aa[i] += 5 aa[i] %= 10 for i in range(2): aa[i],aa[3 - i] = aa[3 - i],aa[i] for i in range(3,-1,-1): stdout.write(str(aa[i]))

以上实例输出结果为：

输入四个数字:
1234
9876

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Python 练习实例72

Python 练习实例90

10 篇笔记写笔记

#10

参考方案：

#!/usr/bin/python
# -*- coding: UTF-8 -*-

n=raw_input()
n = str(n)
a=[]
for i in range(4):
    a.append(int(n[i])+5)
a[0],a[3]=a[3],a[0]
a[1],a[2]=a[2],a[1]
print "".join('%s' %s for s in a)

叮咚3年前 (2017-04-26)

参考方法：

# coding:utf-8
num=int(input("请输入一个四位整数:"))
num=str(num)
List=[]
for i in range(0,len(num)):
    a=(int(num[i])+5)%10
    List.append(a)

List[0],List[3]=List[3],List[0]
List[1],List[2]=List[2],List[1]
print(List[0]*1000+List[1]*100+List[2]*10+List[3])

朦胧3年前 (2017-06-15)

参考方法：

#!/usr/bin/python
# -*- coding: UTF-8 -*-

if __name__ == '__main__':
    a = str(raw_input('输入一个要加密的四位数字:'))
    L = []
    for i in range(len(a)):
        L.append(a[i])
    for i in range(len(L)):
        L[i] = (int(L[i]) + 5) % 10
    L.reverse()
    print L

轮子着火了3年前 (2017-06-19)

参考方法：

#!/usr/bin/python
# -*- coding: UTF-8 -*-

def encode(num):
    s = str(num)
    n = ""
    for i in range(len(s)):
        n += str((int(s[i]) + 5) % 10)
    return int(n[::-1])
print(encode(1234))

helloworld3年前 (2017-06-26)

参考方法：

#!/usr/bin/python
# -*- coding: UTF-8 -*-
def codeZip(var):
    if len(str(var))!= 4:
        return 'error'
    a = (var%10+5)%10
    b = (var/10%10+5)%10
    c = (var/100%10+5)%10
    d = (var/1000+5)%10
    return d+c*10+b*100+a*1000
print codeZip(1234)

haha3年前 (2017-07-27)

Python2.x 与 Python3.x 测试实例：

def example89():
    val=[12,43,13,45]
    newval=[(i+5)%10 for i in val]
    l=len(newval)
    for i in range(0,l//2):
        newval[i],newval[l-i-1]=newval[l-i-1],newval[i]
    print(newval)
example89()

墨雨3年前 (2017-09-12)

# -*- coding: UTF-8 -*-

a = str(raw_input("输入四个数字：\n"))
c = ""
for i in range(4):
    b = int(a[i:i+1:1])
    b += 5
    b %= 10
    b = str(b)
    c = b + c
print c

木叶苍蓝2年前 (2017-10-15)

参考方法：

# coding:utf-8

s = reversed('1234')
l = []
for idx, i in enumerate(s):
    l.append((int(i) + 5) % 10)

print (''.join(str(i) for i in l))

shizi2年前 (2017-10-23)

参考方法：

# coding:utf-8

def func():
    n = str(raw_input("请输入四位整数"))
    a = str((int(n[:1])+5)%10)
    b = str((int(n[1:2])+5)%10)
    c = str((int(n[2:3])+5)%10)
    d = str((int(n[3:4])+5)%10)
    number = d+c+b+a
    print number
func()

凉城的夜2年前 (2017-11-02)

解码与编码：

#!/usr/bin/python
# -*- coding: UTF-8 -*-

def encode(strm):
    strn = list(strm)
    lens = len(strn)
    for i in range(lens):
        j = int(strn[i])-int('0')+5
        j %= 10
        strn[i] = j
    for i in range(lens/2+1):
        strn[i],strn[lens-1-i] = strn[lens-1-i], strn[i]
    strdata = ''
    for i in range(lens):
        strdata += str(strn[i])
    return strdata

    

def decode(strm):
    strn = list(strm)
    lens = len(strn)
    for i in range(lens/2+1):
        strn[i],strn[lens-1-i] = strn[lens-1-i], strn[i]
    for i in range(lens):
        j = int(strn[i])- int('0') + 10
        j -= 5
        j %= 10
        strn[i] = str(j)
    strdata = ''
    for i in range(lens):
        strdata += str(strn[i])
    return strdata

if __name__ == '__main__':
    strn = '9485333'
    print 'transfer data:', strn
    stren = encode(strn)
    print stren
    strde = decode(stren)
    print strde

kamiya2年前 (2017-11-17)